What is the derivative of arctan(2/x) ?

The derivative of arctan(2/x) is -2/(4+x^2)

What is the first derivative of arctan(2/x) ?

The first derivative of arctan(2/x) is -2/(4+x^2)

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derivative of

arctan (\frac{2}{x})

- \frac{2}{4 + x ^{2}}

Solution steps

\frac{d}{d x} (arctan (\frac{2}{x}))

Apply the chain rule:

\frac{1}{( \frac{2}{x} ) ^{2} + 1} \frac{d}{d x} (\frac{2}{x})

= \frac{1}{( \frac{2}{x} ) ^{2} + 1} \frac{d}{d x} (\frac{2}{x})

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= \frac{1}{( \frac{2}{x} ) ^{2} + 1} (- \frac{2}{x ^{2}})

Simplify

\frac{1}{( \frac{2}{x} ) ^{2} + 1} (- \frac{2}{x ^{2}}) : - \frac{2}{4 + x ^{2}}

= - \frac{2}{4 + x ^{2}}

x^{2} y^{^{''}} + y^{^{'}} = 0

\int_{0}^{1} x^{6} (1 + 2 x^{7})^{5} d x

f (x) = x^{4} sec (5 x)

\frac{\partial}{\partial x} (sin (x^{2}) y)

\int_{2}^{\infty} e^{- 5 x} d x

What is the derivative of arctan(2/x) ?
The derivative of arctan(2/x) is -2/(4+x^2)
What is the first derivative of arctan(2/x) ?
The first derivative of arctan(2/x) is -2/(4+x^2)