What is the derivative of 2x^2+cos^2(x) ?

The derivative of 2x^2+cos^2(x) is 4x-sin(2x)

What is the first derivative of 2x^2+cos^2(x) ?

The first derivative of 2x^2+cos^2(x) is 4x-sin(2x)

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\frac{d}{d x} (2 x^{2} + cos^{2} (x))

4 x - sin (2 x)

Solution steps

\frac{d}{d x} (2 x^{2} + cos^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (cos^{2} (x))

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (cos^{2} (x)) = - sin (2 x)

= 4 x - sin (2 x)

\frac{d}{d x} (cos (\frac{3 x ^{2}}{x + 2}))

x \to 2 lim ([7 f (x) + g (x)])

\frac{d y}{d x}, x y = 56

\frac{\partial}{\partial x} (sin (π (x - 4 y)))

\int (6 x^{2} - 4 x + 3) d x

What is the derivative of 2x^2+cos^2(x) ?
The derivative of 2x^2+cos^2(x) is 4x-sin(2x)
What is the first derivative of 2x^2+cos^2(x) ?
The first derivative of 2x^2+cos^2(x) is 4x-sin(2x)