What is implicit (dy)/(dx),e^{(9xy)}=10x ?

The answer to implicit (dy)/(dx),e^{(9xy)}=10x is (dy)/(dx)=(10-9e^{9xy}y)/(9e^{9xy)x}

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implicit (dy)/(dx),e^{(9xy)}=10x

implicit derivative

\frac{d y}{d x}, e^{(9 x y)} = 10 x

\frac{d y}{d x} = \frac{10 - 9 e ^{9 x y} y}{9 e ^{9 x y} x}

Solution steps

e^{9 x y} = 10 x

Treat

y

y (x)

Differentiate both sides:

e^{9 x y} \cdot 9 (y + x \frac{d y}{d x}) = 10

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{10 - 9 e ^{9 x y} y}{9 e ^{9 x y} x}

\frac{d y}{d x} = \frac{10 - 9 e ^{9 x y} y}{9 e ^{9 x y} x}

\int \frac{1}{2} cos (2 x) d x

e^{y} \frac{d y}{d x} = 2 x

\int 20 y d y

\frac{d}{d x} (ln (arcsin (2 x)))

\frac{d}{d x} (\frac{tan ( x )}{cos ( x )})

What is implicit (dy)/(dx),e^{(9xy)}=10x ?
The answer to implicit (dy)/(dx),e^{(9xy)}=10x is (dy)/(dx)=(10-9e^{9xy}y)/(9e^{9xy)x}