What is the integral of 1 (e^{x^2}y) ?

The integral of 1 (e^{x^2}y) is dy(sqrt(pi))/2 \erfi(x)+C

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integral of 1 (e^{x^2}y)

\int \frac{d}{1} (e^{x^{2}} y) d x

d y \frac{π}{2} erfi (x) + C

Solution steps

\int \frac{d}{1} e^{x^{2}} y d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d y \cdot \int e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= d y \frac{π}{2} erfi (x)

Add a constant to the solution

= d y \frac{π}{2} erfi (x) + C

\frac{d y}{d x} = - 5 + x + y

\frac{200}{0.9 + 0.1 e ^{2 h}}

\int \frac{\frac{1}{z} - x ^{2}}{x ^{2}} d x

\int (sec^{2} (θ) - sin (θ)) d θ

What is the integral of 1 (e^{x^2}y) ?
The integral of 1 (e^{x^2}y) is dy(sqrt(pi))/2 \erfi(x)+C