What is the derivative of acos(bx+c+d) ?

The derivative of acos(bx+c+d) is -absin(bx+c)

What is the first derivative of acos(bx+c+d) ?

The first derivative of acos(bx+c+d) is -absin(bx+c)

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\frac{d}{d x} (a cos (b x + c) + d)

- ab sin (b x + c)

Solution steps

\frac{d}{d x} (a cos (b x + c) + d)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (b x + c)) + \frac{dd}{d x}

\frac{d}{d x} (a cos (b x + c)) = - ab sin (b x + c)

\frac{dd}{d x} = 0

= - ab sin (b x + c) + 0

Simplify

= - ab sin (b x + c)

6 x^{2} - 2 x, x^{3} - 6 x + 3

\int (2^{0} - 3^{0})^{x} d x

f (x) = 3 x + 1

(2 x - 1) d x + (5 y + 9) d y = 0

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} - 4 x - 5)

What is the derivative of acos(bx+c+d) ?
The derivative of acos(bx+c+d) is -absin(bx+c)
What is the first derivative of acos(bx+c+d) ?
The first derivative of acos(bx+c+d) is -absin(bx+c)