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Popular >

y^'=(4+3x)^4

Solution

y^{^{'}} = (4 + 3 x)^{4}

Solution

y = \frac{1}{15} (4 + 3 x)^{5} + c_{1}

Solution steps

y^{'} (x) = (4 + 3 x)^{4}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (4 + 3 x)^{4} d x

\int (4 + 3 x)^{4} d x = \frac{1}{15} (4 + 3 x)^{5} + c_{1}

y = \frac{1}{15} (4 + 3 x)^{5} + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(4+3x)^4 ?
The solution for y^'=(4+3x)^4 is y= 1/15 (4+3x)^5+c_{1}