What is (\partial)/(\partial x)(ln(x+y+z)) ?

The answer to (\partial)/(\partial x)(ln(x+y+z)) is 1/(x+y+z)

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(\partial)/(\partial x)(ln(x+y+z))

\frac{\partial}{\partial x} (ln (x + y + z))

\frac{1}{x + y + z}

Solution steps

\frac{\partial}{\partial x} (ln (x + y + z))

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{x + y + z} \frac{\partial}{\partial x} (x + y + z)

= \frac{1}{x + y + z} \frac{\partial}{\partial x} (x + y + z)

\frac{\partial}{\partial x} (x + y + z) = 1

= \frac{1}{x + y + z} \cdot 1

Simplify

= \frac{1}{x + y + z}

f (x) = \frac{1}{2} e^{2 x}

\int x^{2} - 3 x + 2 d x

\int \frac{( x ^{2} - x + 5 )}{x} d x

\frac{d}{d x} (1 + 2 x^{2})

y^{^{''}} - \frac{5}{x} y^{^{'}} + \frac{8}{x ^{2}} y = 0

What is (\partial)/(\partial x)(ln(x+y+z)) ?
The answer to (\partial)/(\partial x)(ln(x+y+z)) is 1/(x+y+z)