What is the integral of (2-3/(x^{10)}) ?

The integral of (2-3/(x^{10)}) is 2x+1/(3x^9)+C

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integral of (2-3/(x^{10)})

\int (2 - \frac{3}{x ^{10}}) d x

2 x + \frac{1}{3 x ^{9}} + C

Solution steps

\int 2 - \frac{3}{x ^{10}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x - \int \frac{3}{x ^{10}} d x

\int 2 d x = 2 x

\int \frac{3}{x ^{10}} d x = - \frac{1}{3 x ^{9}}

= 2 x - (- \frac{1}{3 x ^{9}})

Simplify

= 2 x + \frac{1}{3 x ^{9}}

Add a constant to the solution

= 2 x + \frac{1}{3 x ^{9}} + C

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\int e^{x^{- \frac{1}{2}}} d x

\int \frac{1}{2 x ^{2} - 4 x + 14} d x

What is the integral of (2-3/(x^{10)}) ?
The integral of (2-3/(x^{10)}) is 2x+1/(3x^9)+C