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Popular >

derivative of ee^xe^{x^2}

Solution

\frac{d}{d x} (e e^{x} e^{x^{2}})

Solution

e^{1 + x + x^{2}} (2 x + 1)

Solution steps

\frac{d}{d x} (e e^{x} e^{x^{2}})

Simplify

e e^{x} e^{x^{2}} : e^{1 + x + x^{2}}

= \frac{d}{d x} (e^{1 + x + x^{2}})

Apply the chain rule:

e^{1 + x + x^{2}} \frac{d}{d x} (1 + x + x^{2})

= e^{1 + x + x^{2}} \frac{d}{d x} (1 + x + x^{2})

\frac{d}{d x} (1 + x + x^{2}) = 2 x + 1

= e^{1 + x + x^{2}} (2 x + 1)

Popular Examples

integral from 0 to 1 of (8+x)/(1+x^2)

\int_{0}^{1} \frac{8 + x}{1 + x ^{2}} d x

inverse oflaplace (5+s)/(s(s^2-5s+4))inverse laplace

\frac{5 + s}{s ( s ^{2} - 5 s + 4 )}

derivative of 3/5

\frac{d}{d x} (\frac{3}{5})

derivative of (1+2x)/(1-2x)derivative of

\frac{1 + 2 x}{1 - 2 x}

sum from n=9 to infinity of e^{3-6n}

n = 9 \sum \infty e^{3 - 6 n}

Frequently Asked Questions (FAQ)

What is the derivative of ee^xe^{x^2} ?
The derivative of ee^xe^{x^2} is e^{1+x+x^2}(2x+1)
What is the first derivative of ee^xe^{x^2} ?
The first derivative of ee^xe^{x^2} is e^{1+x+x^2}(2x+1)