What is the integral from 2 to infinity of 1/(3x) ?

The integral from 2 to infinity of 1/(3x) is diverges

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integral from 2 to infinity of 1/(3x)

\int_{2}^{\infty} \frac{1}{3 x} d x

diverges

Solution steps

\int_{2}^{\infty} \frac{1}{3 x} d x

Compute the indefinite integral:

\int \frac{1}{3 x} d x = \frac{1}{3} ln ∣ x ∣ + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{3 x} d x =

diverges

= diverges

r^{2} - 13 x^{2}

y^{^{'}} = 3 - 2 x - 0.5 y, y (0) = 1

\frac{d}{d x} ((ln (x))^{s e c (x)})

\frac{\partial}{\partial y} (x \cdot y^{2} \cdot e^{z})

\int \frac{8}{( x - 5 ) ( x + 3 )} d x

What is the integral from 2 to infinity of 1/(3x) ?
The integral from 2 to infinity of 1/(3x) is diverges