What is the derivative of (x^2/(x^2-9)) ?

The derivative of (x^2/(x^2-9)) is -(18x)/((x^2-9)^2)

What is the first derivative of (x^2/(x^2-9)) ?

The first derivative of (x^2/(x^2-9)) is -(18x)/((x^2-9)^2)

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\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 9})

- \frac{18 x}{( x ^{2} - 9 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x ^{2} - 9 ) - \frac{d}{d x} ( x ^{2} - 9 ) x ^{2}}{( x ^{2} - 9 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{2} - 9) = 2 x

= \frac{2 x ( x ^{2} - 9 ) - 2 x x ^{2}}{( x ^{2} - 9 ) ^{2}}

Simplify

\frac{2 x ( x ^{2} - 9 ) - 2 x x ^{2}}{( x ^{2} - 9 ) ^{2}} : - \frac{18 x}{( x ^{2} - 9 ) ^{2}}

= - \frac{18 x}{( x ^{2} - 9 ) ^{2}}

\frac{\partial}{\partial x} ((y - 2) tan (y))

y = - 3 sin (4 - 3 x^{4})

\frac{d}{d x} (- 0.1 x^{2} + 40 x)

(2 x + 1)^{5}

y = x^{\frac{2}{5}} + 6 x

What is the derivative of (x^2/(x^2-9)) ?
The derivative of (x^2/(x^2-9)) is -(18x)/((x^2-9)^2)
What is the first derivative of (x^2/(x^2-9)) ?
The first derivative of (x^2/(x^2-9)) is -(18x)/((x^2-9)^2)