What is 1/2 x^2ln^2(x)-2x^2ln(x)+5/2 x^2 ?

The solution to 1/2 x^2ln^2(x)-2x^2ln(x)+5/2 x^2 is (x^2ln^2(x)+5x^2)/2-2x^2ln(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/2 x^2ln^2(x)-2x^2ln(x)+5/2 x^2

simplify

\frac{1}{2} x^{2} ln^{2} (x) - 2 x^{2} ln (x) + \frac{5}{2} x^{2}

\frac{x ^{2} ln ^{2} ( x ) + 5 x ^{2}}{2} - 2 x^{2} ln (x)

Solution steps

\frac{1}{2} x^{2} ln^{2} (x) - 2 x^{2} ln (x) + \frac{5}{2} x^{2}

\frac{1}{2} x^{2} ln^{2} (x) = \frac{x ^{2}}{2} ln^{2} (x)

\frac{5}{2} x^{2} = \frac{5 x ^{2}}{2}

= \frac{x ^{2}}{2} ln^{2} (x) - 2 x^{2} ln (x) + \frac{5 x ^{2}}{2}

Multiply

ln^{2} (x) \frac{x ^{2}}{2} : \frac{x ^{2} ln ^{2} ( x )}{2}

= \frac{x ^{2} ln ^{2} ( x )}{2} - 2 x^{2} ln (x) + \frac{5 x ^{2}}{2}

Combine the fractions

\frac{x ^{2} ln ^{2} ( x )}{2} + \frac{5 x ^{2}}{2} : \frac{x ^{2} ln ^{2} ( x ) + 5 x ^{2}}{2}

= \frac{x ^{2} ln ^{2} ( x ) + 5 x ^{2}}{2} - 2 x^{2} ln (x)

\frac{d}{d x} (\frac{- 7 sin ( x )}{4 cos ( x )})

f (x) = 3 x^{4} (x^{2} - 4 x)

x \to 3 lim (\frac{∣ 3 - x ∣}{3 - x})

\int \frac{x ^{2}}{x + 15} d x

\int_{1}^{3} (x^{2} + \frac{1}{4 x ^{2}}) d x

What is 1/2 x^2ln^2(x)-2x^2ln(x)+5/2 x^2 ?
The solution to 1/2 x^2ln^2(x)-2x^2ln(x)+5/2 x^2 is (x^2ln^2(x)+5x^2)/2-2x^2ln(x)