What is laplacetransform T+2 ?

The answer to laplacetransform T+2 is 1/(s^2)+2/s

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laplacetransform T+2

laplace transform

T + 2

\frac{1}{s ^{2}} + \frac{2}{s}

Solution steps

L {T + 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {T} + L {2}

L {T} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} + \frac{2}{s}

y^{^{'}} = - y + 5

x \to 1 lim (\frac{x - 3}{2})

\frac{d}{d x} (arctan (5 cos (x)))

k = 1 \sum \infty \frac{1}{4 ^{k}}

1 + x^{2}

What is laplacetransform T+2 ?
The answer to laplacetransform T+2 is 1/(s^2)+2/s