What is the tangent of y=5x^{1/2}+x^{3/2},\at x=25 ?

The tangent of y=5x^{1/2}+x^{3/2},\at x=25 is y=8x-50

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tangent of y=5x^{1/2}+x^{3/2},\at x=25

tangent of

y = 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}, at x = 25

y = 8 x - 50

Solution steps

Find the tangent point:

(25, 150)

Find the slope of

y = 5 x^{\frac{1}{2}} + x^{\frac{3}{2}} : \frac{d y}{d x} = \frac{5}{2 x ^{\frac{1}{2}}} + \frac{3 x ^{\frac{1}{2}}}{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(25, 150) : y = 8 x - 50

y = 8 x - 50

\frac{\partial}{\partial x} (ln (3))

\int e^{- 2 t} t^{2} d t

cos (u)

\int (21 x^{2} - 60 x + 17) d x

\frac{\partial}{\partial x} (x^{2} y + 3 e^{x y})

What is the tangent of y=5x^{1/2}+x^{3/2},\at x=25 ?
The tangent of y=5x^{1/2}+x^{3/2},\at x=25 is y=8x-50