What is the derivative of f(x)=sqrt(2x+2) ?

The derivative of f(x)=sqrt(2x+2) is 1/(sqrt(2x+2))

What is the first derivative of f(x)=sqrt(2x+2) ?

The first derivative of f(x)=sqrt(2x+2) is 1/(sqrt(2x+2))

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derivative of

f (x) = 2 x + 2

\frac{1}{2 x + 2}

Solution steps

\frac{d}{d x} (2 x + 2)

Apply the chain rule:

\frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

= \frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{2 2 x + 2} \cdot 2

Simplify

\frac{1}{2 2 x + 2} \cdot 2 : \frac{1}{2 x + 2}

= \frac{1}{2 x + 2}

\frac{d y}{d x} = 0.0016 y (2400 - y)

x \to 4 lim (\frac{7}{x - 4})

x \to 0 lim (3 x^{2} + 5)

ln (x^{2} + 1)

\int \frac{1}{x ^{2} + x + 1} d x

What is the derivative of f(x)=sqrt(2x+2) ?
The derivative of f(x)=sqrt(2x+2) is 1/(sqrt(2x+2))
What is the first derivative of f(x)=sqrt(2x+2) ?
The first derivative of f(x)=sqrt(2x+2) is 1/(sqrt(2x+2))