What is the integral from 0 to 10 of |x^2-6x+5| ?

The integral from 0 to 10 of |x^2-6x+5| is 314/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 10 of |x^2-6x+5|

\int_{0}^{10} x^{2} - 6 x + 5 d x

\frac{314}{3}

Decimal

104.66666 \dots

Solution steps

\int_{0}^{10} x^{2} - 6 x + 5 d x

Eliminate Absolutes

= \int_{0}^{1} x^{2} - 6 x + 5 d x + \int_{1}^{5} - x^{2} + 6 x - 5 d x + \int_{5}^{10} x^{2} - 6 x + 5 d x

\int_{0}^{1} x^{2} - 6 x + 5 d x = \frac{7}{3}

\int_{1}^{5} - x^{2} + 6 x - 5 d x = \frac{32}{3}

\int_{5}^{10} x^{2} - 6 x + 5 d x = \frac{275}{3}

= \frac{7}{3} + \frac{32}{3} + \frac{275}{3}

Simplify

\frac{7}{3} + \frac{32}{3} + \frac{275}{3} : \frac{314}{3}

= \frac{314}{3}

n = 1 \sum \infty \frac{1}{100 n}

\int \frac{1}{16} e^{- 4 x} d x

\frac{d}{d t} (t^{- 2})

\int e^{s} sin (t - s) d s

\frac{d}{d x} (3 x^{2} 25 - x^{2})

What is the integral from 0 to 10 of |x^2-6x+5| ?
The integral from 0 to 10 of |x^2-6x+5| is 314/3