What is implicit (dy)/(dx),x^2y=1 ?

The answer to implicit (dy)/(dx),x^2y=1 is (dy}{dx}=-\frac{2y)/x

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implicit (dy)/(dx),x^2y=1

implicit derivative

\frac{d y}{d x}, x^{2} y = 1

\frac{d y}{d x} = - \frac{2 y}{x}

Solution steps

x^{2} y = 1

Treat

y

y (x)

Differentiate both sides:

2 x y + \frac{d y}{d x} x^{2} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{2 y}{x}

\frac{d y}{d x} = - \frac{2 y}{x}

\int \frac{2 x}{λ ^{2}} d x

x \to 0 lim (\frac{e ^{4 x} - 1}{2 x ^{2} + 2 x})

\int sin (x) sin (n) x d x

n = 1 \sum \infty \frac{4}{n ( n + 6 )}

\int sin^{4} (x) cos^{3} (x) d x

What is implicit (dy)/(dx),x^2y=1 ?
The answer to implicit (dy)/(dx),x^2y=1 is (dy}{dx}=-\frac{2y)/x