What is the derivative of 1936-16t^2 ?

The derivative of 1936-16t^2 is -32t

What is the first derivative of 1936-16t^2 ?

The first derivative of 1936-16t^2 is -32t

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derivative of

1936 - 16 t^{2}

- 32 t

Solution steps

\frac{d}{d t} (1936 - 16 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1936) - \frac{d}{d t} (16 t^{2})

\frac{d}{d t} (1936) = 0

\frac{d}{d t} (16 t^{2}) = 32 t

= 0 - 32 t

Simplify

= - 32 t

\frac{x}{x - 5}

(3.2) (5.6)

y = (x - 2) (2 x + 3)

\frac{d}{d x} (12 - x)

x \to \infty lim (\frac{x ^{3}}{1 e ^{\frac{x}{2}}})

What is the derivative of 1936-16t^2 ?
The derivative of 1936-16t^2 is -32t
What is the first derivative of 1936-16t^2 ?
The first derivative of 1936-16t^2 is -32t