What is the derivative of 2+x^2+x ?

The derivative of 2+x^2+x is 2x+1

What is the first derivative of 2+x^2+x ?

The first derivative of 2+x^2+x is 2x+1

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\frac{d}{d x} (2 + x^{2} + x)

2 x + 1

Solution steps

\frac{d}{d x} (2 + x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 0 + 2 x + 1

Simplify

= 2 x + 1

y = 4 x - x^{2}, y = x, x = 3

\frac{12 x}{x ^{2} - 4}

x \to \infty lim (\frac{0}{3})

f (x) = \frac{x}{x ^{3} + 1}

\int (6 x - x^{2}) d x

What is the derivative of 2+x^2+x ?
The derivative of 2+x^2+x is 2x+1
What is the first derivative of 2+x^2+x ?
The first derivative of 2+x^2+x is 2x+1