What is maclaurin (x+3)(-2n(6n-1)(-2x)^{n-1}) ?

The answer to maclaurin (x+3)(-2n(6n-1)(-2x)^{n-1}) is \ldots

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maclaurin (x+3)(-2n(6n-1)(-2x)^{n-1})

maclaurin

(x + 3) (- 2 n (6 n - 1) (- 2 x)^{n - 1})

\dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( ( x + 3 ) ( - 2 n ( 6 n - 1 ) ( - 2 x ) ^{n - 1} ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ( x + 3 ) ( - 2 n ( 6 n - 1 ) ( - 2 x ) ^{n - 1} ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ( x + 3 ) ( - 2 n ( 6 n - 1 ) ( - 2 x ) ^{n - 1} ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} x + \frac{0}{2 !} x^{2} + \dots

Refine

= \dots

\frac{s ^{2}}{s ^{2} + 6 s + 34}

\frac{d}{d x} (\frac{x - 3}{x + 1})

f (x) = \frac{1}{x ^{3}}, (1, 1)

\int sin^{2} (10 x) d x

\int (x + 3) (2 x - 1) d x

What is maclaurin (x+3)(-2n(6n-1)(-2x)^{n-1}) ?
The answer to maclaurin (x+3)(-2n(6n-1)(-2x)^{n-1}) is \ldots