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Popular >

derivative of f(t)=e^{8tsin(2t)}

Solution

derivative of

f (t) = e^{8 t s i n (2 t)}

Solution

e^{8 t s i n (2 t)} \cdot 8 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{8 t s i n (2 t)})

Apply the chain rule:

e^{8 t s i n (2 t)} \frac{d}{d t} (8 t sin (2 t))

= e^{8 t s i n (2 t)} \frac{d}{d t} (8 t sin (2 t))

\frac{d}{d t} (8 t sin (2 t)) = 8 (sin (2 t) + 2 t cos (2 t))

= e^{8 t s i n (2 t)} \cdot 8 (sin (2 t) + 2 t cos (2 t))

Graph

Popular Examples

(\partial)/(\partial x)(3x^2y^4-2)

\frac{\partial}{\partial x} (3 x^{2} y^{4} - 2)

integral of (5x-7)e^{5x-7}

\int (5 x - 7) e^{5 x - 7} d x

integral of te^{-3t}

\int t e^{- 3 t} d t

derivative of g(t)=(t-sqrt(t))/(t^{1/9)}derivative of

g (t) = \frac{t - t}{t ^{\frac{1}{9}}}

x^2y^{''}+7xy^'+5y=0

x^{2} y^{^{''}} + 7 x y^{^{'}} + 5 y = 0

Frequently Asked Questions (FAQ)

What is the derivative of f(t)=e^{8tsin(2t)} ?
The derivative of f(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))
What is the first derivative of f(t)=e^{8tsin(2t)} ?
The first derivative of f(t)=e^{8tsin(2t)} is e^{8tsin(2t)}*8(sin(2t)+2tcos(2t))