What is the derivative of (2-7x^{3/2}^2) ?

The derivative of (2-7x^{3/2}^2) is -21x^{1/2}(2-7x^{3/2})

What is the first derivative of (2-7x^{3/2}^2) ?

The first derivative of (2-7x^{3/2}^2) is -21x^{1/2}(2-7x^{3/2})

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\frac{d}{d x} ((2 - 7 x^{\frac{3}{2}})^{2})

- 21 x^{\frac{1}{2}} (2 - 7 x^{\frac{3}{2}})

Solution steps

\frac{d}{d x} ((2 - 7 x^{\frac{3}{2}})^{2})

Apply the chain rule:

2 (2 - 7 x^{\frac{3}{2}}) \frac{d}{d x} (2 - 7 x^{\frac{3}{2}})

= 2 (2 - 7 x^{\frac{3}{2}}) \frac{d}{d x} (2 - 7 x^{\frac{3}{2}})

\frac{d}{d x} (2 - 7 x^{\frac{3}{2}}) = - \frac{21 x ^{\frac{1}{2}}}{2}

= 2 (2 - 7 x^{\frac{3}{2}}) (- \frac{21 x ^{\frac{1}{2}}}{2})

Simplify

2 (2 - 7 x^{\frac{3}{2}}) (- \frac{21 x ^{\frac{1}{2}}}{2}) : - 21 x^{\frac{1}{2}} (2 - 7 x^{\frac{3}{2}})

= - 21 x^{\frac{1}{2}} (2 - 7 x^{\frac{3}{2}})

y^{^{'}} + e^{x} y = 1

2 x^{^{''}} + 4 x^{^{'}} + 8 x = 0, x (0) = 0, x^{^{'}} (0) = 1

\frac{d}{d θ} (e^{- i θ})

\frac{\partial}{\partial x} (ln (tan (\frac{x}{2})))

\int \frac{1 - x ^{2}}{x} d x

What is the derivative of (2-7x^{3/2}^2) ?
The derivative of (2-7x^{3/2}^2) is -21x^{1/2}(2-7x^{3/2})
What is the first derivative of (2-7x^{3/2}^2) ?
The first derivative of (2-7x^{3/2}^2) is -21x^{1/2}(2-7x^{3/2})