What is the integral from x to infinity of e^{-y} ?

The integral from x to infinity of e^{-y} is e^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x to infinity of e^{-y}

\int_{x}^{\infty} e^{- y} d y

e^{- x}

Solution steps

\int_{x}^{\infty} e^{- y} d y

Compute the indefinite integral:

\int e^{- y} d y = - e^{- y} + C

Compute the boundaries:

\int_{x}^{\infty} e^{- y} d y = 0 - (- e^{- x})

= 0 - (- e^{- x})

Simplify

= e^{- x}

\frac{d y}{d x} = \frac{x y + 2 x - y - 2}{x y - 5 x + 6 y - 30}

\int \frac{1}{4 1 + x} d x

\int \frac{1}{( a ^{2} + x ^{2} ) ^{\frac{5}{2}}} d x

\frac{d}{d a} (b lo g_{10} (\frac{y}{x} + \frac{0.6 x}{a}))

y = x^{\frac{4}{3}}, y = 2 x^{\frac{1}{3}}

What is the integral from x to infinity of e^{-y} ?
The integral from x to infinity of e^{-y} is e^{-x}