What is the derivative of 6e^{-8x} ?

The derivative of 6e^{-8x} is -48e^{-8x}

What is the first derivative of 6e^{-8x} ?

The first derivative of 6e^{-8x} is -48e^{-8x}

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\frac{d}{d x} (6 e^{- 8 x})

- 48 e^{- 8 x}

Solution steps

\frac{d}{d x} (6 e^{- 8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (e^{- 8 x})

Apply the chain rule:

e^{- 8 x} \frac{d}{d x} (- 8 x)

= e^{- 8 x} \frac{d}{d x} (- 8 x)

\frac{d}{d x} (- 8 x) = - 8

= 6 e^{- 8 x} (- 8)

Simplify

= - 48 e^{- 8 x}

f (x) = 2 x + 1, (4, 3)

(x^{3} - 4 x) (2 x^{2} + 5 x)

\int e^{t (a - s)} d t

\int_{0}^{1} cos^{2} (3 π x) d x

n = 1 \sum \infty n p (1 - p)^{n}

What is the derivative of 6e^{-8x} ?
The derivative of 6e^{-8x} is -48e^{-8x}
What is the first derivative of 6e^{-8x} ?
The first derivative of 6e^{-8x} is -48e^{-8x}