What is the slope of y=sin(xy)+pi,(1,pi) ?

The slope of y=sin(xy)+pi,(1,pi) is -pi/2

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slope of y=sin(xy)+pi,(1,pi)

slope

y = sin (x y) + π, (1, π)

- \frac{π}{2}

Solution steps

y = sin (x y) + π

Use implicit differentiation to find the slope of

y = sin (x y) + π

Implicit Derivative

\frac{d y}{d x}

y = sin (x y) + π : \frac{y cos ( x y )}{1 - x cos ( x y )}

\frac{y cos ( x y )}{1 - x cos ( x y )}

Find the slope at

(1, π) : - \frac{π}{2}

- \frac{π}{2}

f (x) = x^{4} + 3 e^{x}, at x = 0

\int 42 x (x + 7)^{5} d x

\frac{d}{d x} (26 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

y^{^{'}} = 3 y^{2} + x y^{2}, y (0) = 1

\int e^{t} (sin (t) + cos (t)) d t

What is the slope of y=sin(xy)+pi,(1,pi) ?
The slope of y=sin(xy)+pi,(1,pi) is -pi/2