What is the integral from 1 to infinity of 1/(x^0) ?

The integral from 1 to infinity of 1/(x^0) is diverges

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integral from 1 to infinity of 1/(x^0)

\int_{1}^{\infty} \frac{1}{x ^{0}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{0}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{0}} d x = x + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{0}} d x =

diverges

= diverges

(1 - \frac{2}{y} + x) \frac{d y}{d x} + y = 2 x - 1

\int_{- 1}^{1} (e^{x})^{2} d x

\int (\frac{5}{t ^{2}} + 4 t^{2}) d t

\int \frac{1}{5 - x ^{2}} d x

\frac{d}{d x} (20 x^{3} - 6 x^{2} + x)

What is the integral from 1 to infinity of 1/(x^0) ?
The integral from 1 to infinity of 1/(x^0) is diverges