What is the derivative of 2x^2-1/16 ln(x) ?

The derivative of 2x^2-1/16 ln(x) is 4x-1/(16x)

What is the first derivative of 2x^2-1/16 ln(x) ?

The first derivative of 2x^2-1/16 ln(x) is 4x-1/(16x)

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derivative of

2 x^{2} - \frac{1}{16} ln (x)

4 x - \frac{1}{16 x}

Solution steps

\frac{d}{d x} (2 x^{2} - \frac{1}{16} ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (\frac{1}{16} ln (x))

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (\frac{1}{16} ln (x)) = \frac{1}{16 x}

= 4 x - \frac{1}{16 x}

\int cos^{3} (x) sin^{6} (x) d x

y = 8 i n^{x} + c

t \to 0 + lim (arctan (\frac{1}{t}))

\int (4 cos (θ))^{2} d θ

\frac{\partial}{\partial t} (e^{s i n (x + c t)})

What is the derivative of 2x^2-1/16 ln(x) ?
The derivative of 2x^2-1/16 ln(x) is 4x-1/(16x)
What is the first derivative of 2x^2-1/16 ln(x) ?
The first derivative of 2x^2-1/16 ln(x) is 4x-1/(16x)