What is the solution for (dy}{dt}+\frac{23y)/t = 1/t ?

The solution for (dy}{dt}+\frac{23y)/t = 1/t is y=(c_{1})/(23t^{23)}+1/23

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(dy}{dt}+\frac{23y)/t = 1/t

\frac{d y}{d t} + \frac{23 y}{t} = \frac{1}{t}

y = \frac{c _{1}}{23 t ^{23}} + \frac{1}{23}

Solution steps

\frac{d y}{d t} + \frac{23 y}{t} = \frac{1}{t}

Solve separable ODE:

y = \frac{c _{1}}{23 t ^{23}} + \frac{1}{23}

y = \frac{c _{1}}{23 t ^{23}} + \frac{1}{23}

1390 - 34 x, 88 x, [11.3934400000000 \dots, 12.3934400000000 \dots]

\frac{\partial}{\partial x} (x y^{2} e^{y})

y^{^{''}} - 4 y^{^{'}} + 8 = 0

\int \frac{1}{1 + z ^{2}} d z

t^{2} y^{^{''}} + 13 t y^{^{'}} + 36 y = 0

What is the solution for (dy}{dt}+\frac{23y)/t = 1/t ?
The solution for (dy}{dt}+\frac{23y)/t = 1/t is y=(c_{1})/(23t^{23)}+1/23