What is the derivative of f(x)=n!(3-x)^{-1} ?

The derivative of f(x)=n!(3-x)^{-1} is (n!)/((3-x)^2)

What is the first derivative of f(x)=n!(3-x)^{-1} ?

The first derivative of f(x)=n!(3-x)^{-1} is (n!)/((3-x)^2)

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derivative of

f (x) = n! (3 - x)^{- 1}

\frac{n !}{( 3 - x ) ^{2}}

Solution steps

\frac{d}{d x} (n! (3 - x)^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= n! \frac{d}{d x} ((3 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 - x ) ^{2}} \frac{d}{d x} (3 - x)

= - \frac{1}{( 3 - x ) ^{2}} \frac{d}{d x} (3 - x)

\frac{d}{d x} (3 - x) = - 1

= n! (- \frac{1}{( 3 - x ) ^{2}} (- 1))

Simplify

n! (- \frac{1}{( 3 - x ) ^{2}} (- 1)) : \frac{n !}{( 3 - x ) ^{2}}

= \frac{n !}{( 3 - x ) ^{2}}

\frac{\partial}{\partial x} (x y^{2} e^{y})

y^{^{''}} - 4 y^{^{'}} + 8 = 0

\int (x^{2} + 4)^{- 2} d x

\int \frac{1}{1 + z ^{2}} d z

t^{2} y^{^{''}} + 13 t y^{^{'}} + 36 y = 0

What is the derivative of f(x)=n!(3-x)^{-1} ?
The derivative of f(x)=n!(3-x)^{-1} is (n!)/((3-x)^2)
What is the first derivative of f(x)=n!(3-x)^{-1} ?
The first derivative of f(x)=n!(3-x)^{-1} is (n!)/((3-x)^2)