What is the solution for 9y^{''}-60y^'+51y=0,y(0)=1,y^'(0)=0 ?

The solution for 9y^{''}-60y^'+51y=0,y(0)=1,y^'(0)=0 is y=(1-17/14)e^{(17t)/3}+17/14 e^t

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9y^{''}-60y^'+51y=0,y(0)=1,y^'(0)=0

9 y^{^{''}} - 60 y^{^{'}} + 51 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y = (1 - \frac{17}{14}) e^{\frac{17 t}{3}} + \frac{17}{14} e^{t}

Solution steps

9 y^{''} (t) - 60 y^{'} (t) + 51 y = 0

Solve linear ODE:

y = (1 - \frac{17}{14}) e^{\frac{17 t}{3}} + \frac{17}{14} e^{t}

y = (1 - \frac{17}{14}) e^{\frac{17 t}{3}} + \frac{17}{14} e^{t}

\frac{d}{d x} ((sin (2 x) + 1)^{2})

y = x^{2} - 1, (- 2, 3)

f (x) = 4 x^{2} - 4 x + 1, at x = 4

\frac{\partial}{\partial x} (y \cdot e^{x})

f (x) = \frac{x}{x + 3}

What is the solution for 9y^{''}-60y^'+51y=0,y(0)=1,y^'(0)=0 ?
The solution for 9y^{''}-60y^'+51y=0,y(0)=1,y^'(0)=0 is y=(1-17/14)e^{(17t)/3}+17/14 e^t