What is the derivative of sin^2(pit) ?

The derivative of sin^2(pit) is pisin(2pit)

What is the first derivative of sin^2(pit) ?

The first derivative of sin^2(pit) is pisin(2pit)

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derivative of

sin^{2} (π t)

π sin (2 π t)

Solution steps

\frac{d}{d t} (sin^{2} (π t))

Apply the chain rule:

2 sin (π t) \frac{d}{d t} (sin (π t))

= 2 sin (π t) \frac{d}{d t} (sin (π t))

\frac{d}{d t} (sin (π t)) = cos (π t) π

= 2 sin (π t) cos (π t) π

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= π sin (2 π t)

n = 1 \sum \infty n

\int_{- \infty}^{0} \frac{1}{4 - 7 x} d x

t \to - 2 lim (\frac{t + 2}{t ^{3} + 8})

e^{x - 2} - \frac{x}{2}

x \to - 2 - lim (\frac{1}{x ^{2} - 4})

What is the derivative of sin^2(pit) ?
The derivative of sin^2(pit) is pisin(2pit)
What is the first derivative of sin^2(pit) ?
The first derivative of sin^2(pit) is pisin(2pit)