What is the integral of xcos(ax^2) ?

The integral of xcos(ax^2) is 1/(2a)sin(ax^2)+C

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integral of xcos(ax^2)

\int x cos (a x^{2}) d x

\frac{1}{2 a} sin (a x^{2}) + C

Solution steps

\int x cos (a x^{2}) d x

Apply u-substitution

: \int \frac{cos ( a u )}{2} d u

= \int \frac{cos ( a u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int cos (a u) d u

Apply u-substitution

: \int \frac{cos ( v )}{a} d v

= \frac{1}{2} \cdot \int \frac{cos ( v )}{a} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{a} \cdot \int cos (v) d v

Use the common integral:

\int cos (v) d v = sin (v)

= \frac{1}{2} \cdot \frac{1}{a} sin (v)

Substitute back

= \frac{1}{2} \cdot \frac{1}{a} sin (a x^{2})

Simplify

\frac{1}{2} \cdot \frac{1}{a} sin (a x^{2}) : \frac{1}{2 a} sin (a x^{2})

= \frac{1}{2 a} sin (a x^{2})

Add a constant to the solution

= \frac{1}{2 a} sin (a x^{2}) + C

\int_{0}^{\infty} 14 e^{- 7 x} d x

8 x - 3

x \to 0 lim (x cot (5 x))

\int (2 x - 5) (x - 3)^{9} d x

(y^{2} + 16) d x - (\frac{1}{( 3 x + 5 ) ^{2}}) d y = 0

What is the integral of xcos(ax^2) ?
The integral of xcos(ax^2) is 1/(2a)sin(ax^2)+C