What is the derivative of t/(t+1) ?

The derivative of t/(t+1) is 1/((t+1)^2)

What is the first derivative of t/(t+1) ?

The first derivative of t/(t+1) is 1/((t+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{t}{t + 1}

\frac{1}{( t + 1 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{t}{t + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d t}{d t} ( t + 1 ) - \frac{d}{d t} ( t + 1 ) t}{( t + 1 ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} (t + 1) = 1

= \frac{1 \cdot ( t + 1 ) - 1 \cdot t}{( t + 1 ) ^{2}}

1 \cdot (t + 1) - 1 \cdot t = 1

= \frac{1}{( t + 1 ) ^{2}}

\int cot^{3} (11 x) d x

y = x^{3} - 3 x + 2 (2.4)

\int tan^{5} (π x) sec^{4} (π x) d x

x^{4} + 7 x^{2} - x

\int 2 x^{3} (3 x^{4} - 5) d x

What is the derivative of t/(t+1) ?
The derivative of t/(t+1) is 1/((t+1)^2)
What is the first derivative of t/(t+1) ?
The first derivative of t/(t+1) is 1/((t+1)^2)