What is the derivative of f(x)=x^{2.4}+e^{2.4} ?

The derivative of f(x)=x^{2.4}+e^{2.4} is 2.4x^{1.4}

What is the first derivative of f(x)=x^{2.4}+e^{2.4} ?

The first derivative of f(x)=x^{2.4}+e^{2.4} is 2.4x^{1.4}

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derivative of

f (x) = x^{2.4} + e^{2.4}

2.4 x^{1.4}

Solution steps

\frac{d}{d x} (x^{2.4} + e^{2.4})

Simplify

x^{2.4} + e^{2.4} : x^{2.4} + 11.02317 \dots

= \frac{d}{d x} (x^{2.4} + 11.02317 \dots)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2.4}) + \frac{d}{d x} (11.02317 \dots)

\frac{d}{d x} (x^{2.4}) = 2.4 x^{1.4}

\frac{d}{d x} (11.02317 \dots) = 0

= 2.4 x^{1.4} + 0

Simplify

= 2.4 x^{1.4}

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What is the derivative of f(x)=x^{2.4}+e^{2.4} ?
The derivative of f(x)=x^{2.4}+e^{2.4} is 2.4x^{1.4}
What is the first derivative of f(x)=x^{2.4}+e^{2.4} ?
The first derivative of f(x)=x^{2.4}+e^{2.4} is 2.4x^{1.4}