What is the tangent of f(x)=((x-2)/(x+2))^2,\at x=-1 ?

The tangent of f(x)=((x-2)/(x+2))^2,\at x=-1 is y=-24x-15

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tangent of f(x)=((x-2)/(x+2))^2,\at x=-1

tangent of

f (x) = (\frac{x - 2}{x + 2})^{2}, at x = - 1

y = - 24 x - 15

Solution steps

Find the tangent point:

(- 1, 9)

Find the slope of

f (x) = (\frac{x - 2}{x + 2})^{2} : \frac{df ( x )}{d x} = \frac{8 ( x - 2 )}{( x + 2 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 24

Find the line with slope m=

- 24

and passing through

(- 1, 9) : y = - 24 x - 15

y = - 24 x - 15

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What is the tangent of f(x)=((x-2)/(x+2))^2,\at x=-1 ?
The tangent of f(x)=((x-2)/(x+2))^2,\at x=-1 is y=-24x-15