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Popular >

integral from-2 to-1 of u-1/(u^2)

Solution

\int_{- 2}^{- 1} u - \frac{1}{u ^{2}} d u

Solution

- 2

Solution steps

\int_{- 2}^{- 1} u - \frac{1}{u ^{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} u d u - \int_{- 2}^{- 1} \frac{1}{u ^{2}} d u

\int_{- 2}^{- 1} u d u = - \frac{3}{2}

\int_{- 2}^{- 1} \frac{1}{u ^{2}} d u = \frac{1}{2}

= - \frac{3}{2} - \frac{1}{2}

Simplify

- \frac{3}{2} - \frac{1}{2} : - 2

= - 2

Graph

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limit as x approaches 2+of (x+3)/(x-2)

x \to 2 + lim (\frac{x + 3}{x - 2})

Frequently Asked Questions (FAQ)

What is the integral from-2 to-1 of u-1/(u^2) ?
The integral from-2 to-1 of u-1/(u^2) is -2