What is the tangent of f(x)= 6/x ,\at x=1 ?

The tangent of f(x)= 6/x ,\at x=1 is y=-6x+12

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tangent of f(x)= 6/x ,\at x=1

tangent of

f (x) = \frac{6}{x}, at x = 1

y = - 6 x + 12

Solution steps

Find the tangent point:

(1, 6)

Find the slope of

f (x) = \frac{6}{x} : \frac{df ( x )}{d x} = - \frac{6}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(1, 6) : y = - 6 x + 12

y = - 6 x + 12

x \to 2 lim (x^{2} - \frac{1}{x})

\frac{1}{s ^{2} ( s + 1 ) ^{2}}

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{2}} d x

x \to 4 - lim (\frac{x - 4}{x - 1})

y = \frac{1}{x}

What is the tangent of f(x)= 6/x ,\at x=1 ?
The tangent of f(x)= 6/x ,\at x=1 is y=-6x+12