What is (\partial)/(\partial x)(y/(2x+3y)) ?

The answer to (\partial)/(\partial x)(y/(2x+3y)) is -(2y)/((2x+3y)^2)

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(\partial)/(\partial x)(y/(2x+3y))

\frac{\partial}{\partial x} (\frac{y}{2 x + 3 y})

- \frac{2 y}{( 2 x + 3 y ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y}{2 x + 3 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (\frac{1}{2 x + 3 y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= y \frac{\partial}{\partial x} ((2 x + 3 y)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 3 y ) ^{2}} \frac{\partial}{\partial x} (2 x + 3 y)

= - \frac{1}{( 2 x + 3 y ) ^{2}} \frac{\partial}{\partial x} (2 x + 3 y)

\frac{\partial}{\partial x} (2 x + 3 y) = 2

= y (- \frac{1}{( 2 x + 3 y ) ^{2}} \cdot 2)

Simplify

y (- \frac{1}{( 2 x + 3 y ) ^{2}} \cdot 2) : - \frac{2 y}{( 2 x + 3 y ) ^{2}}

= - \frac{2 y}{( 2 x + 3 y ) ^{2}}

n = 1 \sum \infty \frac{( n + 4 )}{n ^{2}}

x \to 3 lim (2 x^{2} - 2)

\frac{d y}{d x} + y^{7} x + y = 0

\frac{d}{d x} (\frac{3 cos ( x )}{1 - 2 sin ( x )})

\frac{\partial}{\partial v} (\frac{u - v}{3})

What is (\partial)/(\partial x)(y/(2x+3y)) ?
The answer to (\partial)/(\partial x)(y/(2x+3y)) is -(2y)/((2x+3y)^2)