What is area 3cos(2x),(3-3cos(2x))x=0x= pi/2 ?

The answer to area 3cos(2x),(3-3cos(2x))x=0x= pi/2 is 3

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area 3cos(2x),(3-3cos(2x))x=0x= pi/2

area

3 cos (2 x), (3 - 3 cos (2 x)) x = 0 x = \frac{π}{2}

3

Solution steps

Apply the area formula:

\int_{\frac{π}{4}}^{\frac{3 π}{4}} 3 ∣ cos (2 x) ∣ d x

Solve

\int_{\frac{π}{4}}^{\frac{3 π}{4}} 3 ∣ cos (2 x) ∣ d x : 3

The area is:

= 3

\int_{0}^{1} π (5 x)^{2} d x

\frac{d}{d x} (5 - 5 x^{2})

6 y^{^{''}} - 6 y^{^{'}} + 75 y = 0

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (2) = 0

ln (ln (7 x))

What is area 3cos(2x),(3-3cos(2x))x=0x= pi/2 ?
The answer to area 3cos(2x),(3-3cos(2x))x=0x= pi/2 is 3