What is inverse oflaplace-5 ?

The answer to inverse oflaplace-5 is -5\delta(t)

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inverse oflaplace-5

inverse laplace

- 5

- 5 δ (t)

Solution steps

L^{- 1} {- 5}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {5}

L^{- 1} {5} : 5 δ (t)

= - 5 δ (t)

x^{2}, 3 - 2 x

\frac{d y}{d x} = x y, y (0) = 1, y (1) = 2

\frac{d}{d x} (2 π - x cos (x))

cos^{2} (x) sin (x) \frac{d y}{d x} cos^{3} (x) y = 1

H (t - 2 π) sin (t - 2 π)