What is (\partial)/(\partial y)(xy+z) ?

The answer to (\partial)/(\partial y)(xy+z) is x

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(\partial)/(\partial y)(xy+z)

\frac{\partial}{\partial y} (x y + z)

x

Solution steps

\frac{\partial}{\partial y} (x y + z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (z) = 0

= x + 0

Simplify

= x

\frac{d}{d x} (\frac{1}{( 2 x + 3 ) ^{3}})

y = x^{2} ln (7 x)

a \to \infty lim (a^{2})

\int_{1}^{6} \frac{6}{x} d x

\frac{d}{d x} (\frac{e ^{s i n (x)}}{2 + cos ( π ) x})

What is (\partial)/(\partial y)(xy+z) ?
The answer to (\partial)/(\partial y)(xy+z) is x