What is the integral from 0 to 4 of pi(4-y) ?

The integral from 0 to 4 of pi(4-y) is 8pi

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integral from 0 to 4 of pi(4-y)

\int_{0}^{4} π (4 - y) d y

8 π

Decimal

25.13274 \dots

Solution steps

\int_{0}^{4} π (4 - y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{4} 4 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{4} 4 d y - \int_{0}^{4} y d y)

\int_{0}^{4} 4 d y = 16

\int_{0}^{4} y d y = 8

= π (16 - 8)

Simplify

= 8 π

\frac{\partial}{\partial y} (x^{4} + y^{4} - 4 x y + 1)

\int x^{3} + x d x

\frac{d y}{d x} = 6 x^{2} e^{- y}

\int (y^{3} + 1.8 y^{2} - 2.4 y) d y

x \to - 2 lim (\frac{3 x - 1}{x})

What is the integral from 0 to 4 of pi(4-y) ?
The integral from 0 to 4 of pi(4-y) is 8pi