What is the derivative of (3x-x^3+1^4) ?

The derivative of (3x-x^3+1^4) is 4(3x-x^3+1)^3(-3x^2+3)

What is the first derivative of (3x-x^3+1^4) ?

The first derivative of (3x-x^3+1^4) is 4(3x-x^3+1)^3(-3x^2+3)

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\frac{d}{d x} ((3 x - x^{3} + 1)^{4})

4 (3 x - x^{3} + 1)^{3} (- 3 x^{2} + 3)

Solution steps

\frac{d}{d x} ((3 x - x^{3} + 1)^{4})

Apply the chain rule:

4 (3 x - x^{3} + 1)^{3} \frac{d}{d x} (3 x - x^{3} + 1)

= 4 (3 x - x^{3} + 1)^{3} \frac{d}{d x} (3 x - x^{3} + 1)

\frac{d}{d x} (3 x - x^{3} + 1) = - 3 x^{2} + 3

= 4 (3 x - x^{3} + 1)^{3} (- 3 x^{2} + 3)

\frac{d}{d t} (s sin (t))

\int_{0}^{500} 6 (700 y - y^{2}) d y

\int (40 - \frac{2}{sec ( θ )}) d θ

f (y) = e^{2 y}

\int_{- 2}^{1} - x^{2} - x + 2 d x

What is the derivative of (3x-x^3+1^4) ?
The derivative of (3x-x^3+1^4) is 4(3x-x^3+1)^3(-3x^2+3)
What is the first derivative of (3x-x^3+1^4) ?
The first derivative of (3x-x^3+1^4) is 4(3x-x^3+1)^3(-3x^2+3)