What is the tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 ?

The tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 is y=-16x+12

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tangent of f(x)= 4/(sqrt(x)),\at x= 1/4

tangent of

f (x) = \frac{4}{x}, at x = \frac{1}{4}

y = - 16 x + 12

Solution steps

Find the tangent point:

(\frac{1}{4}, 8)

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 16

Find the line with slope m=

- 16

and passing through

(\frac{1}{4}, 8) : y = - 16 x + 12

y = - 16 x + 12

\int_{1}^{4} - 3 t ln (t) d t

\int_{0}^{5} 2 π x (\frac{1}{x + 4}) d x

- 1.621 s - 0.462945095

\frac{\partial}{\partial φ} (ρ sin (φ) cos (θ))

y^{^{''}} - 4 y^{^{'}} + 5 y = 2020 e^{- t}

What is the tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 ?
The tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 is y=-16x+12