What is the derivative of y=(1-e^x)^2 ?

The derivative of y=(1-e^x)^2 is -2e^x(1-e^x)

What is the first derivative of y=(1-e^x)^2 ?

The first derivative of y=(1-e^x)^2 is -2e^x(1-e^x)

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derivative of

y = (1 - e^{x})^{2}

- 2 e^{x} (1 - e^{x})

Solution steps

\frac{d}{d x} ((1 - e^{x})^{2})

Apply the chain rule:

2 (1 - e^{x}) \frac{d}{d x} (1 - e^{x})

= 2 (1 - e^{x}) \frac{d}{d x} (1 - e^{x})

\frac{d}{d x} (1 - e^{x}) = - e^{x}

= 2 (1 - e^{x}) (- e^{x})

Simplify

= - 2 e^{x} (1 - e^{x})

y^{^{'}} = ry + k

\frac{d}{d x} (\frac{1}{( 2 - x ) ^{2}})

\int \frac{2 x - 4 + 6 x}{x} d x

4 x^{2} - 7 x + 5

n = 1 \sum \infty \frac{4}{2 ^{n}}

What is the derivative of y=(1-e^x)^2 ?
The derivative of y=(1-e^x)^2 is -2e^x(1-e^x)
What is the first derivative of y=(1-e^x)^2 ?
The first derivative of y=(1-e^x)^2 is -2e^x(1-e^x)