What is the solution for (dy)/(dt)=2y-3e^{-t},y(0)=1 ?

The solution for (dy)/(dt)=2y-3e^{-t},y(0)=1 is y= 1/(e^t)

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(dy)/(dt)=2y-3e^{-t},y(0)=1

\frac{d y}{d t} = 2 y - 3 e^{- t}, y (0) = 1

y = \frac{1}{e ^{t}}

Solution steps

\frac{d y}{d t} = 2 y - 3 e^{- t}

Solve linear ODE:

y = \frac{1}{e ^{t}}

y = \frac{1}{e ^{t}}

y^{^{''}} + y = x cos^{3} (x)

sin^{2} (7 x)

\int cos (x) 25 - sin^{2} (x) d x

f (t) = (9 t + 2)^{\frac{2}{3}}

\int 19 θ sec^{2} (θ) d θ

What is the solution for (dy)/(dt)=2y-3e^{-t},y(0)=1 ?
The solution for (dy)/(dt)=2y-3e^{-t},y(0)=1 is y= 1/(e^t)