What is the solution for 5y^{''}+35y=0 ?

The solution for 5y^{''}+35y=0 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)

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5y^{''}+35y=0

5 y^{^{''}} + 35 y = 0

y = c_{1} cos (7 t) + c_{2} sin (7 t)

Solution steps

5 y^{''} (t) + 35 y = 0

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t)

x \to 4 + lim (1)

\int \frac{1 + x}{x ^{2}} d x

\frac{d}{d x} (3 9 x + 1)

- 6 \cdot x^{2} \cdot y + \frac{d y}{d x} = 5 x^{2}

\frac{\partial}{\partial x} (3 x^{4} + 5 y^{4} + 9 x y)

What is the solution for 5y^{''}+35y=0 ?
The solution for 5y^{''}+35y=0 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)