What is the integral of sin^3(11x) ?

The integral of sin^3(11x) is 1/11 (-cos(11x)+(cos^3(11x))/3)+C

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integral of sin^3(11x)

\int sin^{3} (11 x) d x

\frac{1}{11} (- cos (11 x) + \frac{cos ^{3} ( 11 x )}{3}) + C

Solution steps

\int sin^{3} (11 x) d x

Apply u-substitution

: \int sin^{3} (u) \frac{1}{11} d u

= \int sin^{3} (u) \frac{1}{11} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{11} \cdot \int sin^{3} (u) d u

Rewrite using trig identities

= \frac{1}{11} \cdot \int (1 - cos^{2} (u)) sin (u) d u

Apply u-substitution

: \int - 1 + v^{2} d v

= \frac{1}{11} \cdot \int - 1 + v^{2} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{11} (- \int 1 d v + \int v^{2} d v)

\int 1 d v = v

\int v^{2} d v = \frac{v ^{3}}{3}

= \frac{1}{11} (- v + \frac{v ^{3}}{3})

Substitute back

= \frac{1}{11} (- cos (11 x) + \frac{cos ^{3} ( 11 x )}{3})

Add a constant to the solution

= \frac{1}{11} (- cos (11 x) + \frac{cos ^{3} ( 11 x )}{3}) + C

\int_{- 3}^{3} (9 - x^{2}) d x

\frac{π}{2}

\int \frac{3 + 4 x}{7 + 3 x + 2 x ^{2}} d x

x \to - 2 lim (\frac{x + 2}{x ^{2} - 4})

x \to 3 lim (- (3 - x))

What is the integral of sin^3(11x) ?
The integral of sin^3(11x) is 1/11 (-cos(11x)+(cos^3(11x))/3)+C