What is (\partial)/(\partial x)(3x^2+9y^2-xy+x) ?

The answer to (\partial)/(\partial x)(3x^2+9y^2-xy+x) is 6x+1-y

Popular >

(\partial)/(\partial x)(3x^2+9y^2-xy+x)

\frac{\partial}{\partial x} (3 x^{2} + 9 y^{2} - x y + x)

6 x + 1 - y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 9 y^{2} - x y + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (9 y^{2}) - \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (9 y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

= 6 x + 0 - y + 1

Simplify

= 6 x + 1 - y

\int \frac{x ^{3} + 5 x ^{4} - 7 x}{x ^{2}} d x

\int_{1}^{2} 5 x - 1 d x

\int_{- \infty}^{3} \frac{1}{x ^{2} + 9} d x

\frac{\partial}{\partial y} (\frac{6 x}{3 x ^{2} - y ^{3} - 3})

\frac{d}{d x} ((x - 1)^{2} \cdot (x - 2) \cdot (x - 4))

What is (\partial)/(\partial x)(3x^2+9y^2-xy+x) ?
The answer to (\partial)/(\partial x)(3x^2+9y^2-xy+x) is 6x+1-y