What is the tangent of x^7-3x^4+7x^3+43,\at x=-2 ?

The tangent of x^7-3x^4+7x^3+43,\at x=-2 is y=628x+1067

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tangent of x^7-3x^4+7x^3+43,\at x=-2

tangent of

x^{7} - 3 x^{4} + 7 x^{3} + 43, at x = - 2

y = 628 x + 1067

Solution steps

Find the tangent point:

(- 2, - 189)

Find the slope of

y = x^{7} - 3 x^{4} + 7 x^{3} + 43 : \frac{d y}{d x} = 7 x^{6} - 12 x^{3} + 21 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 628

Find the line with slope m=

628

and passing through

(- 2, - 189) : y = 628 x + 1067

y = 628 x + 1067

\int \frac{1}{x 1 + x} d x

x \to 0 lim (3 - 4 x)

\int x^{2} + 81 d x

x \to 0 lim (3 x)

y = 2 x^{2} + 7 x, (- 1, - 5)

What is the tangent of x^7-3x^4+7x^3+43,\at x=-2 ?
The tangent of x^7-3x^4+7x^3+43,\at x=-2 is y=628x+1067